Answer: (x1,y1,z1) = (1, 2, 3) (x2,y2,z2) = (-1, -2, -1) (x3,y3,z3) = (2, 3, 2) (x4,y4,z4) = (4, 7, 6) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2}...
Show that the points P(2, 3, 5), Q(-4, 7, -7), R(-2, 1, -10) and S(4, -3, 2) are the vertices of a rectangle.
Answer: (x1,y1,z1) = (2, 3, 5) (x2,y2,z2) = (-4, 7, -7) (x3,y3,z3) = (-2, 1, -10) (x4,y4,z4) = (4, -3, 2) $\begin{array}{l} Length PQ = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} +...
Show that the points P(1, 3, 4), Q(-1, 6, 10), R(-7, 4, 7) and S(-5, 1, 1) are the vertices of a rhombus.
Answer: (x1,y1,z1) = (1, 3, 4) (x2,y2,z2) = (-1, 6, 10) (x3,y3,z3) = (-7, 4, 7) (x4,y4,z4) = (-5, 1, 1) $\begin{array}{l} Length PQ = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2}...
Show that D(-1, 4, -3) is the circumcentre of triangle ABC with vertices A(3, 2, -5), B(-3. 8, -5) and C(-3, 2, 1).
Answer: (x1,y1,z1) = (3, 2, -5) (x2,y2,z2) = (-3, 8, -5) (x3,y3,z3) = (-3, 2, 1) (x4,y4,z4) = (-1, 4, -3) $\begin{array}{l} Length AD = \sqrt {{{({x_4} - {x_1})}^2} + {{({y_4} - {y_1})}^2} +...
Show that the following points are collinear : A(-2, 3, 5), B(1, 2, 3) and C(7, 0, -1)
Answer: (x1,y1,z1) = (-2, 3, 5) (x2,y2,z2) = (1, 2, 3) (x3,y3,z3) = (7, 0, -1) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\...
Show that the following points are collinear : A(3, -5, 1), B(-1, 0, 8) and C(7, -10, -6)
Answer: (x1,y1,z1) = (3, -5, 1) (x2,y2,z2) = (-1, 0, 8) (x3,y3,z3) = (7, -10, -6) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}}...
Show that the following points are collinear : P(3, -2, 4), Q(1, 1, 1) and R(-1, 4, 2)
Answer: (x1,y1,z1) = (3, -2, 4) (x2,y2,z2) = (1, 1, 1) (x3,y3,z3) = (-1, 4, -2) $\begin{array}{l} Length PQ = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\...
Find the equation of the curve formed by the set of all points which are equidistant from the points A(-1, 2, 3) and B(3, 2, 1).
Answer: Let us take, C(x,y,z) point equidistant from points A(-1, 2, 3) and B(3, 2, 1). ∴ AC = BC $\sqrt {{{(x + 1)}^2} + {{(y - 2)}^2} + {{(z - 3)}^2}} = \sqrt {{{(x - 3)}^2} + {{(y - 2)}^2} +...
Find the point on the y-axis which is equidistant from the points A(3, 1, 2) and B(5, 5, 2).
Answer: Let us take, C(0,y,0) point which lies on y axis and is equidistant from points A(3, 1, 2) and B(5, 5, 2). ∴ AC = BC $\sqrt {{{(0 - 3)}^2} + {{(y - 1)}^2} + {{(0 - 2)}^2}} = \sqrt {{{(0 -...
Find the point on the z-axis which is equidistant from the points A(1, 5, 7) and B(5, 1, -4).
Answer: Let us take, C(0,0,z) point which lies on z axis and is equidistant from points A(1, 5, 7) and B(5, 1, -4). ∴ AC = BC $\sqrt {{{(0 - 1)}^2} + {{(0 - 5)}^2} + {{(z - 7)}^2}} = \sqrt {{{(0 -...
Find the coordinates of the point which is equidistant from the points A(a, 0, 0), B(0, b, 0), C(0, 0, c) and O(0, 0, 0).
Answer: Let us take, D(x,y,z) point equidistant from points A(a, 0, 0), B(0, b, 0), C(0, 0, c) and O(0, 0, 0). ∴ AD = OD $\sqrt {{{(x - a)}^2} + {{(y - 0)}^2} + {{(z - 0)}^2}} = \sqrt {{{(x -...
Find the point in yz-plane which is equidistant from the points A(3, 2, -1), B(1, -1, 0) and C(2, 1, 2).
Answer: The general point on yz plane is D(0, y, z). Consider this point is equidistant to the points A(3, 2, -1), B(1, -1, 0) and C(2, 1, 2). ∴ AD = BD $\sqrt {{{(0 - 3)}^2} + {{(y - 2)}^2} + {{(z...
Find the point in xy-plane which is equidistant from the points A(2, 0, 3), B(0, 3, 2) and C(0, 0, 1).
Answer: The general point on xy plane is D(x, y, 0). Consider this point is equidistant to the points A(2, 0, 3), B(0, 3, 2) and C(0, 0, 1). ∴ AD = BD $\sqrt {{{(x - 2)}^2} + {{(y - 0)}^2} + {{(0 -...
Show that the points A(1, 1, 1), B(-2, 4, 1), C(1, -5, 5) and D(2, 2, 5) are the vertices of a square.
Answer: (x1,y1,z1) = (1, 1, 1) (x2,y2,z2) = (-2, 4, 1) (x3,y3,z3) = (1, 5, 5) (x4,y4,z4) = (2, 2, 5) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} -...
Show that the points A(0, 1, 2), B(2, -1, 3) and C(1, -3, 1) are the vertices of an isosceles right-angled triangle.
Answer: (x1,y1,z1) = (0, 1, 2) (x2,y2,z2) = (2, -1, 3) (x3,y3,z3) = (1, -3, 1) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\ =>...
Show that the points A(4, 6, -5), B(0, 2, 3) and C(-4, -4, -1) from the vertices of an isosceles triangle.
Answer: (x1,y1,z1) = (4, 6, -3) (x2,y2,z2) = (0, 2, 3) (x3,y3,z3) = (-4, -4, -1) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\ =>...
Show that the points A(1, -1, -5), B(3, 1,3) and C(9, 1, -3) are the vertices of an equilateral triangle.
Answer: (x1,y1,z1) = (1, -1, -5) (x2,y2,z2) = (3, 1,3) (x3,y3,z3) = (9, 1, -3) $\begin{array}{l} Length AB = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\ =>...
Find the distance between the points : (i) R(1, -3, 4) and S(4, -2, -3) (ii) C(9, -12, -8) and the origin
Answers: (i) R(1, -3, 4) and S(4, -2, -3) (x1,y1,z1) = (1, -3, 4) (x2,y2,z2) = (4, -2, -3) $\begin{array}{l} D = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\ D =...
Find the distance between the points : (i) A(5, 1, 2) and B(4, 6, -1) (ii) P(1, -1, 3) and Q(2, 3, -5)
Answers: (i) A(5, 1, 2) and B(4, 6, -1) (x1,y1,z1) = (5, 1, 2) (x2,y2,z2)= (4, 6, -1) $\begin{array}{l} D = \sqrt {{{({x_2} - {x_1})}^2} + {{({y_2} - {y_1})}^2} + {{({z_2} - {z_1})}^2}} \\ D = \sqrt...