Because energy is required to overcome the attractions between the haloalkane molecules as well as to break the hydrogen bonds between water molecules, haloalkanes are only weakly soluble in water.

Electrophilic substitution can be used to make aryl bromides and chlorides from arenes. In the absence of light, this reaction is carried out by treating the arene with chlorine or bromine in the...

This is due to the aryl ring's resonance stabilisation. There will be a conjugation of chlorine electrons with the electrons in the ring in the case of C6H5-Cl. The partial double bond nature of the...

Iodoform has a significant antibacterial activity due to the release of free iodine.

In an SN1 reaction with the OH- ion, C6H5— CH2— Cl will react quicker. This is owing to the carbocation's stability in the compound. The C6H5 group is already stable owing to resonance, and the CH2...

Arenes' iodination can be reversed due to the production of HI. An oxidising agent, such as HNO3 or HIO4, oxidises HI to speed up the process and stabilise the result.

Option (ii) and (iii) are the answers. Heating an alkyl chloride or bromide in the presence of a metallic fluoride such as AgF, FIg2F2, CoF2, or SbF3 results in the production of alkyl fluorides....

Option (i) and (ii) are the answers (i) $R-\mathrm{OH} \stackrel{\mathrm{HCl}+\mathrm{ZnCl}}{\longrightarrow} R-\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}$ (ii) $R-\mathrm{OH}...

Option (i) and (iii) are the answers. Secondary bromides are those in which the -carbone (bromine-bound carbon) is further attached to two alkyl groups. The -carbon in compounds (i) and (iii) is...

Option (i) and (iii) are the answers. They give ethyne on treatment with alcoholic $\mathrm{KOH}$. $ \mathrm{CH}_{3} \mathrm{CHCl}_{2} \underset{\mathrm{KOH}}{\stackrel{\text { alc....

Option (i) and (iv) are the answers. Halogen atoms are linked to the sp3 hybridised carbon atom of the alkyl group in each of these molecules.

Option (i) and (iv) are the answers. Because it is a tertiary halide, it undergoes the SN1 process, resulting in the formation of a carbocation as an intermediate.  

Option (i) and (iv) are the answers. Intermediate (iii) is unstable in the above reaction because the carbon atom is linked to 5 atoms and is less stable than reactant (ii).

Option (i) and (ii) are the answers. Alkyl halide is the main reactant in the given reaction. A transient condition is found here, in which one bond is broken and another is created synchronously,...

Option (i) and (iii) are the answers. Nucleophiles are HO and CF. The C atom is sp2 hybridised in (iii) due to the simultaneous creation of the C – OH bond and the breakdown of the C – Cl link. As a...

Option (iv) is the answer Reason: As the molecular mass of the alkyl halide grows, the boiling point rises.

Option (i) is the answer. Explanation: The larger the surface area, the stronger the intermolecular forces of attraction and, as a result, the higher the boiling point. For comparable types of alkyl...

Option (iv) is the answer. Electron withdrawing groups boost aryl halide reactivity; the higher the number of electron withdrawing groups, the higher the rate of nucleophilic substitution.

Option (iv) is the answer. The presence of an electron-releasing group in the ortho or para locations slows down nucleophilic substitution.

Option (iii) is the answer. Nucleophilic substitution is facilitated by the presence of an electron withdrawing group (-NO2) in the ortho and para positions. At meta position, the presence of an...

Option (ii) is the answer. The chiral carbon, which is $sp_3$ hybridised carbon attached to four distinct substituents, is known as asymmetric carbon. Because (b) and (c) are $sp_3$ hybridised, they...

Option (iii) is the answer. After reacting with $NH_3$ and chloromethane, methanamine is formed. ​

Option (d) is the answer. In the presence of iron and in the absence of light, toluene reacts with chlorine to produce a mixture of 1-chloro-2-methylbenzene and 1-chloro-4-methylbenzene. The methyl...

Option (iv) is the answer. SN1 reactions occur mostly in polar protic solvents such as H2O and follow first-order kinetics. This indicates that the reaction rate is solely determined by one...

Option (ii) is the answer. Primary alkyl halides undergo SN​2 mechanisms because 1∘ substrates have little steric hindrance to nucleophilic attack and 1∘ carbocations are relatively unstable....

The solution is option (iii). The addition of HCl across the double bond follows the Markovnikov rule in the aforementioned reaction. The negative portion of the addition molecule is linked to the...

Option (ii) is the answer. A gem-dihalide is ethylidene chloride. A compound with two halogen atoms on the same carbon atom is known as Gem Dihalide.

Option (ii) is the answer. Chlorobenzene is formed by the reaction of chlorine with benzene in the presence of AlCl3. Cl+ attacks the benzene ring in this reaction.

Optuion (i) is the answer. A) Allyl : $\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHC}(\mathrm{Br})\left(\mathrm{CH}_{3}\right)_{2}$ B) Aryl: $\mathrm{p}-\mathrm{ClC}_{6} \mathrm{H}_{4} \mathrm{CH}_{2}...

Option (ii) is the answer. Vicinal dihalides are formed when a halogen reacts with an alkene to form compounds with halogen on neighbouring carbons. In terms of yearly output, 1, 2- dichloroethane...

Option (i) is the answer. Enantiomers are a pair of molecules that are mirror copies of one another.

Option (ii) is the answer. Asymmetric carbon atoms are those that have four distinct groups or atoms connected to them. The compounds a,b,c satisfy this criterion, thus B is the right answer.

Option (iii) is the answer. The boiling point of an alkyl halide falls as the branching rises. As a result, tert butyl bromide has the lowest boiling point while n butyl bromide has the greatest...

Option (i) is the answer. Reason:The density of a substance is exactly proportional to its molar mass at constant volume.

Option (i) is the answer. Mono-chlorinated isomeric products of Cl 2/UV light free radical substitution

Option (i) is the answer. Metal–halogen exchange is a basic reaction in organometallic chemistry that transforms an organic halide into an organometallic product. Electropositive metals (Li, Na, Mg)...

Option (ii) is the answer. In the presence of Iron(III) chloride, toluene interacts with halogen to produce ortho and para halo compounds in an electrophilic substitution process. The Cl atom...

Option (i) is the answer.

Option (iv) is the answer. If any alkyl halide forms a more stable carbocation at room temperature, the result is a more stable and efficient product. The formation of a $3^0$ carbocation as an...