ACCORDING TO QUES, \[~\left( 1\text{ }+~{{y}^{2}} \right)\text{ }ta{{n}^{1}}x\text{ }dx~+\text{ }2y~\left( 1\text{ }+~{{x}^{2}} \right)~dy~=\text{ }0\] \[2y\text{ }\left( 1\text{ }+\text{ }{{x}^{2}}...
ACCORDING TO QUES, DIFFERENTIATING WITH RESPECT TO x ,
according to ques,
Option (i) is correct Teflon is a chemically inert and thermally stable material that is used to make nonstick cookware.
Option (i) is correct Polymerization of olefins like ethene results in polymers like polythene.
Option (ii) is correct. Rayon is a semi-synthetic polymer that is a better alternative than cotton because acetylation improves the characteristics of cellulose after processing.
(i) is f (ii) is e (iii) is a (iv) is c (v) is b (vi) is d
(i) is b (ii) is d (iii) is a (iv) is d (v) is c
(i) is e (ii) is c (iii) is a (iv) is b (v) is d
Pure monomers are employed instead of polymerization through the free radical pathway because even little impurities serve as inhibitors, causing the chain reaction to abruptly stop and short length...
Proteins and synthetic polyamides share certain structural similarities. Polyamides, such as Nylon, are made up of Glycine and aminocaproic acid molecules linked together by an amide bond. A similar...
In laminated sheets, urea-formaldehyde resin is utilised. The monomeric components used to make laminated sheets are urea and formaldehyde.
By providing chain initiation, benzoyl peroxide functions as an initiator in free radical addition polymerisation of alkenes. The generated radical reacts with the carbon-carbon double bond of an...
Cross-linking is used to increase these physical qualities by assisting in the binding of its planar polymer sheets, therefore improving elastomeric properties and thermal stability.
Proteins, nucleic acids, and starch are all examples of step-growth polymers. Condensation polymers are step growth polymers. The loss of a simple molecule allows monomers with bifunctional or...
This is polyisoprene or natural rubber. This polymer's monomeric unit is 2-methyl-1,3-butadiene.
In this polymer chain, the monomers A' and 'B' are randomly linked. As an example, this is a copolymer. A When a mixture of two or more unsaturated monomers reacts, a copolymer is formed.
The monomer in this case is –A-. This polymer is a homopolymer since the same or same monomer is repeated to make it.
The structure of 2-methyl-1,3-butadiene is Rubber vulcanization is the term for this procedure. Sulphur works as a crosslinking agent in this case, stiffening the rubber and giving it better...
Option (i) and (iv) are the answers. Rubber becomes more elastic and rigid after vulcanization. Sulphur produces cross connections at the reactive locations of double bonds or at their reactive...
Option (i), (ii) and (iv) are the answers. The vinylic monomer units of acrilan, polystyrene, and teflon are as follows:
Option (i) and (ii) are the answers. Biodegradable polymers are those that are quickly degraded and are not hazardous to the environment.
Option (i) and (iv) are the answers. Bakelite is a phenol and formaldehyde condensation polymer. Melamine formaldehyde resin is a melamine (2, 4, 6-triamino-1, 3, 5-triazine) and formaldehyde...
Option (iii) and (iv) are the answers. The addition polymers Orion and polystyrene are produced by polymerizing CH2 = CH – CN (acrylonitrile) and C6H5 – CH = CH2 styrene, respectively.
Option (ii) and (iii) are the answers. (b) (c)
Option (iv) is the answer. Nylon -6 is a polymer made from caprolactam polymerization.
Option (i) is the answer.
Option (ii) is the answer. Low density polythene is a strong yet flexible (not too flexible) material with a weak electrical conductivity. Its structure is extremely branching.
Option (i) is the answer. Condensation polymerization of ethylene glycol and phthalic acid with the removal of the water molecule yields the given polymer.
Option (C) is the answer. Biodegradable polymers are materials whose chemical and physical properties deteriorate and disintegrate entirely when exposed to microorganisms, aerobic, and anaerobic...
Option (ii) is the answer.
Option (i) is the answer M-polyisoprene is a polymer that comes from nature.
Option (iv) is the answer. Glycogen is a glucose polymer present in animal livers, brains, and muscles. Amylase and amylopectin are structural components of starch, while cellulose is a polymer...
Solution: (c) arrangement of cycle by linkage between metal particle and ligand balances out the coordination compound. The ligand which chelates the metal particle are known as chelating ligand....
according to ques,
According to ques, or, \[\left( x~+~y \right)\text{ }\left( dx~~dy \right)\text{ }=~dx~+~dy\] \[\left( x\text{ }+\text{ }y \right)\text{ }dx\text{ }\text{ }\left( x\text{ }\text{ }y \right)\text{...
according to ques,
according to ques,
according to ques,
according to ques,
According to ques, Equation will be, \[{{\left( x\text{ }\text{ }0 \right)}^{2}}~+\text{ }{{\left( y\text{ }\text{ }a \right)}^{2}}~=\text{ }{{a}^{2}},\] where (0, a) is the centre...
according to ques,
according to ques,
according to ques,
according to ques,
according to ques, we can write,
According to ques we have, \[~ydx\text{ }\text{ }xdy\text{ }=\text{ }{{x}^{2}}ydx\] or, \[y\text{ }dx\text{ }\text{ }{{x}^{2}}y\text{ }dx\text{ }=\text{ }xdy\] \[y\text{ }\left( 1\text{ }\text{...
ACCORDING TO QUES, \[dy/dx\text{ }+\text{ }1\text{ }=\text{ }{{e}^{x+y}}\] NOW PUTTING, \[x\text{ }+\text{ }y\text{ }=\text{ }t\] and differentiating w.r.t. x,
ACCORDING TO QUES, \[dy/dx\text{ }+\text{ }ay\text{ }=\text{ }{{e}^{mx}}\] for linear differential equation of first order, \[P\text{ }=\text{ }a\text{ }and\text{ }Q\text{ }=\text{...
according to ques, \[dy/dx\text{ }+\text{ }2xy\text{ }=\text{ }y\]
according to ques,
according to ques,
SINCE ,equation of all non-vertical lines is $$ \[~y\text{ }=\text{ }mx\text{ }+\text{ }c\] On differentiating w.r.t. x, \[dy/dx\text{ }=\text{ }m\] and, on differentiating w.r.t. x,...
ACCORDING TO QUES,
Ans:
Let \[~P\left( n \right)\text{ }:\text{ }{{\left( AB \right)}^{n}}~=\text{ }{{A}^{n}}{{B}^{n}}\] In this way, \[P\left( 1 \right)\text{ }:\text{ }{{\left( AB \right)}^{1}}~=\text{...
Ans:
We realize that, \[A\text{ }.\text{ }I\text{ }=\text{ }I\text{ }.\text{ }A\] In this way, \[A\text{ }and\text{ }I\]are commutative. Subsequently, we can grow \[{{\left( I\text{ }+\text{ }A...
Ans:
Ans:
Ans: By utilizing equity of matrixs, we get \[co{{s}^{2}}~\alpha \text{ }+\text{ }si{{n}^{2~}}\alpha \text{ }=\text{ }1\], which is valid for all genuine upsides of \[\alpha .\]
Ans:
Ans: Let, Presently, by equity of matrices, we get \[a\text{ }=\text{ }1,\text{ }b\text{ }=\text{ }-\text{ }2,\text{ }c\text{ }=\text{ }-\text{ }5\] Furthermore, \[2a\text{ }\text{ }d\text{ }=\text{...
Ans: Presently, \[3a\text{ }=\text{ }a\text{ }+\text{ }4\Rightarrow a\text{ }=\text{ }2\] \[3b\text{ }=\text{ }6\text{ }+\text{ }a\text{ }+\text{ }b\] \[3b\text{ }-\text{ }b\text{ }=\text{ }8\]...
Ans:
Ans: How about we think about a matrix C, with the end goal that Looking at the terms, \[\mathbf{2a}\text{ }+\text{ }\mathbf{48}\text{ }=\text{ }\mathbf{0}\text{ }\Rightarrow \text{...
Answer: In the given matrix condition, Looking at the comparing components, we get \[x\text{ }+\text{ }y\text{ }=\text{ }6,\] \[xy\text{ }=\text{ }8,\] \[z\text{ }+\text{ }6\text{ }=\text{ }0\]and...
Ans: Since, we obtain all the zeroes in a row of the matrix A, L.H.S., A-1 does not exist.
Ans:
Ans:
Answer: According to the given ques
Ans:
Answer: According to the given ques,
Answer: According to the given ques, (a) (b)
Answer: According to the given ques
Answer: (a) (b)
Answer: According to the given ques
Given, \[A\text{ }and\text{ }B\]are square matrices with the end goal that \[AB\text{ }=\text{ }BA.\] In this way, \[{{\left( A\text{ }+\text{ }B \right)}^{2}}~=\text{ }\left( A\text{ }+\text{ }B...
As, \[A\text{ }and\text{ }B\]be square matrixs of order \[3\text{ }x\text{ }3.\] We have, \[{{\left( AB \right)}^{2}}~=\text{ }AB\text{ }.\text{ }AB\] \[=\text{ }A\left( BA \right)B\] \[=\text{...
Answer: According to the given ques
Answer: According to the given ques
according to ques,
Answer: According to the given ques
according to ques,
\[x~=~asin2t~(1\text{ }+\text{ }cos2t)~and~y~=~b~cos2t~(1cos2t)\]
Answer: According to the ques
Answer: According to the given matrix, the solution should be
\[x~=~{{e}^{cos2t}}~and~y~=~{{e}^{sin2t}}\] So, \[cos\text{ }2t\text{ }=\text{ }log\text{ }x\] and \[sin\text{ }2t\text{ }=\text{ }log\text{ }y\]
Answer: According to the given matrix, the solution should be
according to ques,
Answer: According to the given matrix, the should be
Answer: According to the given matrix, the solution should be
according to ques,
\[x\text{ }=~3cosq\text{ }\text{ }2co{{s}^{3}}q,~y~=\text{ }3sinq\text{ }\text{ }2si{{n}^{3}}q.\]
Answer: According to the given matix, the solution should be
according to ques,
Answer: From (I) and (ii), Thus, \[AB\text{ }=\text{ }AC\]however \[B\text{ }\ne \text{ }C.\]
Answer: Given, \[A\text{ }=\text{ }{{\left[ 3\text{ }5 \right]}_{1\times 2}}~\]and \[B\text{ }=\text{ }{{\left[ 7\text{ }3 \right]}_{1\times 2}}\] For \[AC\text{ }=\text{ }BC\] We have order of...
according to ques,
according to ques,
Answer: According to the given matix, the solution should be
according to ques,
Answer: Presently, we have \[2x\text{ }+\text{ }3y\text{ }\text{ }8\text{ }=\text{ }0\text{ }\ldots ..\text{ }\left( 1 \right)~\]and \[x\text{ }+\text{ }5y\text{ }\text{ }11\text{ }=\text{ }0\text{...
according to ques,
Answer: From (I) and (ii), we have \[\left( AB \right)\text{ }=\text{ }B\text{ }A\]
according to ques,
according to ques,
Answer: According to the given matrix, the solution should be – Hence Proved
Answer: According to question, the solutions should be
according to ques,
according to ques,
Answer: The provided matrixs \[A\]has order \[3\text{ }x\text{ }2\]and B has order 2 x 3. Thus, \[BA\] is characterized and will have order 3 x 3. Be that as it may, \[{{A}^{2}}~and\text{...
ACCORDING TO QUES,
Answer: On looking at components of the two sides, we have \[4x\text{ }=\text{ }-4\text{ }\Rightarrow x\text{ }=\text{ }-1\] \[4y\text{ }=\text{ }8\text{ }\Rightarrow \text{ }y\text{ }=\text{ }2\]...
ACCORDING TO QUES,
ACCORDING TO QUES,
ANSWER: Presently, \[{{P}^{-1}}~PAQ\text{ }=\text{ }{{P}^{-1~}}I\] Thus, \[IAQ\text{ }=\text{ }{{P}^{-1}}\] \[AQ\text{ }=\text{ }{{P}^{-1}}\] \[AQ{{Q}^{-1}}~=\text{ }{{P}^{-1}}~{{Q}^{-1}}\]...
ACCORDING TO QUES,
Ozone is less thermodynamically stable because it decomposes into oxygen and this decay leads to heat release, so its entropy is positive whereas the free energy is negative for this ozone.
ACCORDING TO QUES,
As the decrease in the electronegativity of the halogen, the tendency of the XO3 group (X = halogens) to withdraw the electrons of the O-H bond has decreased so the perhalic acid strength also...
Reaction Involved: NO3- + 3Fe2+ + 4H+ → NO + 3Fe2 + 2H2O [Fe(H2O) 6]SO4 + NO → [Fe(H2O) 5NO]SO4 (brown coloured complex)
Identification: Halide A - PCl5 (yellowish-white powder) Halide B - PCl3 (colourless oily liquid) Reaction Involved: PCl3 + 3H2O H3PO3 + 3HCl (Hydrolysis of PCl5) PCl5 + H2O POCl3+ 2HCl PCl5 +...
ACCORDING TO QUES,
Answer: According to question, the matrix can be solved as Given, Presently, \[{{A}^{2}}-\text{ }3A\text{ }-\text{ }7I\text{ }=\text{ }0\] Increasing the two sides with\[A-1\], we get...
ACCORDING TO QUES,
ACCORDING TO QUES,
ACCORDING TO QUES,
ACCORDING TO QUES,
Fluorine is the most potent oxidizing agent and can oxidize sulfur in its high oxidation state (+6) to form SF6. Chlorine is not a good oxidizing agent, it cannot oxidize sulfur in its high...
H2O has a higher bond angle than H2S because as we move from oxygen to sulfur the size of the central atom increases and electronegativity decreases due to which bond moving from the central atom...
Chlorine has some empty area in the d orbital which is why it can show an oxidation state of +3. Fluorine has no vacancy in the d orbital, it cannot show a good oxidation state. Fluorine shows only...
The nitric acid in the form of a gas is present in the form of a monomer. It contains only one unpaired electron and is therefore paramagnetic. In the solid state, it exists as a dimer (N2O2). There...
The size of the axial bond is greater than the size of the equatorial bond to endure repulsion because the three equatorial bonds create more repulsion. The two axial P-Cl bonds are therefore longer...
ACCORDING TO QUES,
Answer: According to given matrix, the solution should be \[[16\text{ }+\text{ }2x\text{ }+\text{ }10(x)\text{ }+\text{ }12\text{ }+\text{ }{{x}^{2}}~+\text{ }4x]\text{ }=\text{ }0\]...
With water, the PH3 does not form any hydrogen bond. It therefore does not dissolve in water and evaporates as a gas and forms bubbles while the ammonia forms the hydrogen bond and dissolves in water.
Reaction Involved: NH3 + O2 → 4NO + 6H2O The platinum gauze acts as a catalyst to speed up the reaction.
The dissolution of SO3 in water is very exothermic. This leads to the formation of tiny droplets that are corrosive and can even attack the lead pipes used to cover the tower in the communication...
ACCORDING TO QUES,
\[f\left( x \right)\text{ }=\text{ }2f\left( x \right).\]
ACCORDING TO QUES, Therefore, f(x) is not differentiable at \[x\text{ }=\text{ }5.\]
Answer: Thus, from (I) and (ii), \[\left( A\text{ }+\text{ }B \right)\text{ }\left( A\text{ }-\text{ }B \right)\text{ }\ne \text{ }{{A}^{2}}-\text{ }{{B}^{2}}\]
(i) The only type of interactions between particles of noble gases is due to weak dispersion forces. (ii) Ionisation enthalpy of molecular oxygen is very close to that of xenon. (iii) Hydrolysis of...
(i) CaF2+ H2SO4 → CaSO4+ 2HF (ii) 2HI + H2SO4 → I2 + SO2+ 2H2O (iii) Cu + 2H2SO4 → CuSO4 + SO2 + 2H2O (iv) NaCl + H2SO4 → NaHSO4 + HCl Correct Answers: (ii) 2HI + H2SO4 → I2 + SO2+ 2H2O...
(i) S–S bond is present in H2S2O6 (ii) In peroxosulphuric acid (H2SO5) sulphur is in +6 oxidation state. (iii) Iron powder along with Al2O3 and K2O is used as a catalyst in the preparation of NH3 by...
(i) As2O3< SiO2< P2O3< SO2 Acid strength. (ii) AsH3< PH3< NH3 Enthalpy of vaporization. (iii) S < O < Cl < F More negative electron gain enthalpy. (iv) H2O > H2S > H2Se...
According to ques, FUNCTION is differentiable at \[x\text{ }=\text{ }2.\]
(i) All three N—O bond lengths in HNO3 are equal. (ii) All P—Cl bond lengths in PCl5 molecule in the gaseous state are equal. (iii) P4 molecule in white phosphorus have angular strain therefore...
(i) It acts as a bleaching agent in moist conditions. (ii) Its molecule has linear geometry. (iii) It’s dilute solution is used as a disinfectant. (iv) It can be prepared by the reaction of dilute...
(i) Among halogens, radius ratio between iodine and fluorine is maximum. (ii) Leaving F—F bond, all halogens have weaker X—X bond than X—X’ bond in interhalogens. (iii) Among interhalogen compounds,...
(i) It has 6 lone pairs of electrons. (ii) It has six P–P single bonds. (iii) It has three P–P single bonds. (iv) It has four lone pairs of electrons. Correct Answers: (ii) It has six P–P...
(i) F2 > Cl2 > Br2 > I2 - Oxidising power. (ii) MI > MBr > MCl > MF - Ionic character of metal halide. (iii) F2 > Cl2 > Br2 > I2 - Bond dissociation enthalpy. (iv) HI <...
(i) 0 to +5 (ii) 0 to +3 (iii) 0 to –1 (iv) 0 to +1 Correct Answers: (i) 0 to +5 (iii) 0 to –1 Explanation:
NOW ACCORDING TO QUES, AND, HENCE DIFFERENTIABILITY AT \[x\text{ }=\text{ }0.\]
SO, f(x) is not differentiable at \[x\text{ }=\text{ }2.\]
Answer: Given, On looking at the relating components, we get \[2x\text{ }+\text{ }10x\text{ }=\text{ }48\] \[12x\text{ }=\text{ }48\] In this manner, \[x\text{ }=\text{ }4\] It's additionally seen...
Given, \[f\left( x \right)\text{ }=\text{ }\left| sin\text{ }x\text{ }+\text{ }cos\text{ }x \right|\text{ }at\text{ }x\text{ }=\text{ }\pi \] Presently, put \[g\left( x \right)\text{ }=\text{...
Answer: Given, \[matrix\text{ }A\text{ }=\text{ }matrix\text{ }B\] Then, at that point, their comparing components are equivalent. Thus, we have \[{{a}_{11}}~=\text{ }{{b}_{11}};\]\[a\text{ }+\text{...
Now, if f(t) is discontinuous, then \[2-\text{ }\text{ }x\text{ }=\text{ }0\Rightarrow x\text{ }=\text{ }2\] And, \[2x-\text{ }\text{ }1\text{ }=\text{ }0\Rightarrow x\text{ }=\text{...
fun wont be define and continuous \[2x\text{ }+\text{ }5\text{ }=\text{ }0\Rightarrow x\text{ }=\text{ }-5/2\] hence,\[x\text{ }=\text{ }-5/2\] is the point of discontinuity.
(i) 2 (ii) 3 (iii) 4 (iv) 6 Correct Answer: (i) 2 Explanation: In the preparation of HNO3, we get NO gas by catalytic oxidation of ammonia. The moles of NO produced by the oxidation of two...
(i) +3 (ii) +5 (iii) +1 (iv) –3 Correct Answer: (iii) +1 Explanation: NaH2PO2 = 1 + (2x+1) + x + 2(−2) =0 x−1 = 0 x = +1
(i) NH4+ (ii) SiCl4 (iii) SF4 (iv) SO42- Correct Answer: (iii) SF4 Explanation: The shape of SF4 is not tetrahedral.
(i) H2SO5 and H2S2O8 (ii) H2SO5 and H2S2O7 (iii) H2S2O7 and H2S2O8 (iv) H2S2O6 and H2S2O7 Correct Answer: (i) H2SO5 and H2S2O8 Explanation: Peroxides of Sulphur - H2SO5 and...
(i) Cu (ii) S (iii) C (iv) Zn Correct Answer: (iii) C Explanation: When hot conc. H2SO4 acts as a moderately strong oxidising agent, it oxidises both metals and nonmetals. The element Carbon...
(i) –3 to +3 (ii) –3 to 0 (iii) –3 to +5 (iv) 0 to –3 Correct Answer: (i) –3 to +3 Explanation: A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When an...
(i) both O2 and Xe has the same size. (ii) both O2 and Xe has the same electron gain enthalpy. (iii) both O2 and Xe has almost same ionisation enthalpy. (iv) both Xe and O2 are gases Correct...
(i) covalent solid (ii) octahedral structure (iii) ionic solid with [PCl6]+ octahedral and [PCl4]– tetrahedra (iv) ionic solid with [PCl4]+tetrahedral and [PCl6]– octahedral Correct Answer:...
IonReduction potential Eᶱ/V ClO4–Eᶱ = 1.19V IO4–Eᶱ = 1.65V BrO4 –Eᶱ = 1.74V (i) ClO4–> IO4– > BrO4– (ii) IO4– > BrO4– > ClO4– (iii) BrO4– > IO4– > ClO4– (iv) BrO4– > ClO4– >...
(i) ICl2, ClO2 (ii) BrO2-, BrF2+ (iii) ClO2, BrF (iv) CN-, O3 Correct Answer: (ii) BrO2-, BrF2+ Explanation: BrO2- = 35 + 2 * 8 + 1 => 52 BrF2+ = 35 + 2 * 9 - 1 =>...
So, \[-1\text{ }+\text{ }a\text{ }=\text{ }a\text{ }+\text{ }b\text{ }=\text{ }1\text{ }+\text{ }b\] \[-1\text{ }+\text{ }a\text{ }=\text{ }a\text{ }+\text{ }b\text{ }and\text{ }1\text{ }+\text{...
Answer: According to the given ques
(i) "Not p" is the negation of the assertion p. The negation of p is represented by $\sim p$. The truth value of $\sim p$ is the opposite of the truth value of p. The negation of the statement is...
Since the left hand limit is not equal to the right hand limit and both have constant values. so the given function remains discontinuous at \[x\text{ }=\text{ }0.\] ...
(i) "Not p" is the negation of the assertion p. The negation of p is represented by $\sim p$. The truth value of $\sim p$ is the opposite of the truth value of p. The negation of the statement is “2...
Answer: According to the question, the matrix can be solved as
(i) "Not p" is the negation of the statement p. The negation of p is represented by the "$\sim p$." The truth value of $\sim p$ is the opposite of the truth value of p. The negation of the statement...
where A = And B = Answer: The given two matrixs \[A\text{ }and\text{ }B\]are of various orders. Two matrices can be added provided that order for both the matrixs is same. So, the sum of matrices...
Answer: Given, \[matrix\text{ }A\text{ }=\text{ }matrix\text{ }B\] Then, at that point, their comparing components are equivalent. Thus, we have \[{{a}_{11}}~=\text{ }{{b}_{11}};\]\[a\text{ }+\text{...
Leave A alone a \[3\text{ }x\text{ }2\] matrix With the end goal that, \[{{a}_{ij}}~=\text{ }{{e}^{i.x}}sin\text{ }jx;\]where \[1\text{ }\le \text{ }i\text{ }\le \text{ }3;\text{ }1\text{ }\le...
ACCORDING TO QUES,
HENCE K IS \[1\]
We have, \[A\text{ }=\text{ }{{[{{a}_{ij}}]}_{2\times 2}}\] (I) Such that,\[~{{a}_{ij}}~=\text{ }{{\left( i\text{ }\text{ }2j \right)}^{2}}/\text{ }2;\] \[where\text{ }1\text{ }\le \text{ }i\text{...
\[~k\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]
For the given matrix, Elements: \[{{a}_{23}}~=\text{ }{{x}^{2}}~\text{ }y,\text{ }{{a}_{31}}~=\text{ }0,\text{ }{{a}_{12}}~=\text{ }1\]
So, \[7\text{ }=\text{ }2k\] \[k\text{ }=\text{ }7/2\text{ }=\text{ }3.5\] SO VALUE OF K IS \[3.5\]
For the given matrix, (I) The order for the matrix \[A\text{ }is\text{ }3\text{ }x\text{ }3.\] (ii) The number of elements of the matrix \[~=\text{ }3\text{ }x\text{ }3\text{ }=\text{ }9\]
For a provided matrix of order \[m\text{ }x\text{ }n,\]it has \[mn\]components, where \[m\text{ }and\text{ }n\]are normal numbers. Here we have, \[m\text{ }x\text{ }n\text{ }=\text{ }28\] \[\left(...
And hence, f(x) is continuous at \[x\text{ }=\text{ }1.\]
And hence, f(x) is continuous at \[x\text{ }=\text{ }1.\]
And hence, f(x) is discontinuous at \[x\text{ }=\text{ }0.\]
And hence, f(x) is continuous at \[x\text{ }=\text{ }0.\]
And hence, f(x) is continuous at \[x\text{ }=\text{ }0.\]
(i) H2SO4 reduces HI to I2 (ii) HI is of violet colour (iii) HI gets oxidised to I2 (iv) HI changes to HIO3 Correct Answer: (iii) HI gets oxidised to I2 Explanation: Reaction...
(i) a deep blue precipitate of Cu (OH)2 (ii) a deep blue solution of [Cu (NH3)4]2+ (iii) a deep blue solution of Cu(NO3)2 (iv) a deep blue solution of Cu(OH)2.Cu(NO3)2 Correct Answer: (ii) a...
(i) 3 double bonds; 9 single bonds (ii) 6 double bonds; 6 single bonds (iii) 3 double bonds; 12 single bonds (iv) Zero double bonds; 12 single bonds Correct Answer: (ii) 6 double bonds; 6...
(i) Carbon (ii) Nitrogen (iii) Phosphorus (iv) Boron Correct Answer: (iii) Phosphorus Explanation: The element which is involved in the pπ–dπ bonding is Phosphorus.
(i) CO32-, NO3- (ii) ClO3- , CO32- (iii) SO32-, NO3- (iv) ClO3- , SO32– Correct Answer: (i) CO32-, NO3- Explanation: CO32- and NO3- are the pairs of ions that are isoelectronic and...