Communication Systems

A 50 MHz sky wave takes 4.04 ms to reach a receiver via re-transmission from a satellite 600 km above earth’s surface. Assuming re-transmission time by satellite negligible, find the distance between source and receiver. If communication between the two was to be done by Line of Sight (LOS) method, what should size and placement of receiving and transmitting antenna be?

Answer: According to the question, the velocity of waves = 3 × 108 m/s The time to reach a receiver = 4.04 × 10-3 s we know that the height of satellite is: h = 600 km And the radius of earth = 6400...

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The maximum frequency for reflection of sky waves from a certain layer of the ionosphere is found to be f max = 9(Nmax) 1/2, where Nmax is the maximum electron density at that layer of the ionosphere. On a certain day, it is observed that signals of frequencies higher than 5MHz are not received by reflection from the F1 layer of the ionosphere while signals of frequencies higher than 8MHz are not received by reflection from the F2 layer of the ionosphere. Estimate the maximum electron densities of the F1 and F2 layers on that day.

Answer: Expression fpor the maximum frequency is: fmax = 9(Nmax)1/2 According to the question, for Layer F1, fmax = 5 MHz $ {{N}_{\max }}=\frac{F_{\max }^{2}}{9\times 9}=\frac{5\times...

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If the whole earth is to be connected by LOS communication using space waves (no restriction of antenna size or tower height), what is the minimum number of antennas required? Calculate the tower height of these antennas in terms of earths radius?

Answer: We know that the distance or range of transmission tower is given by the expression: $dT=\sqrt{2{{h}_{T}}R}$ R represents the radius of the earth (approximately 6400 km). hT​ denotes the...

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Two waves A and B of frequencies 2 MHz and 3 MHz, respectively are beamed in the same direction for communication via skywave. Which one of these is likely to travel a longer distance in the ionosphere before suffering total internal reflection?

Answer: The refractive index rises as the frequency rises, implying that the angle of refraction is smaller for higher frequency waves. In other words, bending is less. As a result, after covering a...

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A 1 KW signal is transmitted using a communication channel which provides attenuation at the rate of – 2dB per km. If the communication channel has a total length of 5 km, the power of the signal received is [gain in dB = 10 log P0/P1]

(a) 900 W (b) 100 W (c) 990 W (d) 1010 W Answer: The correct option is (b) 100 W Explanation: According to the question, Pi​ =1 kW = 1000W The rate of attenuation of the signal = -2dB/km Length of...

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