Exercise 16C

y=\int _{0}^{\pi /2}\frac{\sin x-\cos x}{1+\sin x\cos x}dx......(1)

Use king theorem of definite integral $\int _{a}^{b}f(x)dx=\int _{a}^{b}f(a+b-x)dx$ $y=\int _{0}^{\pi /2}\frac{\sin \left( \frac{\pi }{2}-x \right)-\cos \left( \frac{\pi }{2}-x \right)}{1+\sin...

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