Answer : Total no.of cases will be 6 x 6 x 6 = 216(because each die can have values from 1 to 6) Desired outcomes are those whose sum up to 5. Desired outcomes are (1, 1, 3), (1, 3, 1), ( 1, 2, 2),...
Answer : All numbers are different (given in question), this will be the same as picking r different objects from n objects which is ncr Here, n= 20 and r = 6(as we have to pick 6 different objects...
Answer : As repetition is not allowed total no.of cases possible is 9×8×7(because if one of the numbers occupies a wheel, then the other wheel cannot be occupied by this number, i.e. next wheel have...
Answer : Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3),...
Answer : (i) We know that, If odds in favor of the occurrence an event are a:b, then the probability of an event to occur is Given, probability We know, probability a/a+b = 5/14 So, a = 5 and a+b...
Answer : We know that, If odds in favor of the occurrence an event are a:b, then the probability of an event to occur is , similarly, if odds are not in the favor of the occurrence an event are...
Answer : We know that, If odds in favor of the occurrence an event are a:b, then the probability of an event to occur is , which indirectly came from Probability of the occurrence of an event...
Answer : We know that, Probability of occurring = 1 - the probability of not occurring Given the probability of occurrence 7/10 Therefore, the probability of not occurrence = 1- 7/10 7/10...
Answer : (i) We know that, If odds in favor of the occurrence an event are a:b, then the probability of an event to occur is Given, probability = 5/14 We know, probability a/a+b 5/14 . So, a = 5...
Answer : We know that, If odds in favor of the occurrence an event are a:b, then the probability of an event to occur similarly, if odds are not in the favor of the occurrence an event are a:b,...
Answer : We know that, If odds in favor of the occurrence an event are a:b, then the probability of an event to Where, Total no.of desired outcomes = a, and total no.of outcomes = a+b Given a = 8,...
Answer : We know that, 7/10 Therefore, the probability of not occurrence Probability of occurring = 1 - the probability of not occurring Given the probability of occurrence 1-7/10 Conclusion:...
Answer : We know that, Probability of occurring = 1 - the probability of not occurring Let’s calculate for the probability of not occurring, i.e. probability such that both of them don’t have a...
Answer : We know that, Probability of occurrence of an event So, we want another Tuesday that to from that 1 day left(as there is only one Tuesday left after 52 weeks)An ordinary year has 365 days...
Answer : We know that, Probability of occurrence of an event Desired output is picking a number which is multiple of 2 or 3. So, desire outputs are 2, 3, 4, 6, 8, 9, 10, 12. Total no.of desired...
Answer : We know that, Probability of occurrence of an event Desired output is a number greater than 3 and less than 10.Total no.of outcomes are 52 There will be four sets of each card naming A, 1,...
Answer : (i) We know that, Probability of occurrence of an event Total possible outcomes are alphabets from a to z Desired outcomes are a, e, i, o, u Conclusion: Probability of choosing a...
Answer : We know that, Probability of occurrence of an event (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3),...
Answer : We know that, Probability of occurrence of an event Let T be tails and H be heads Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH Desired outcomes are at least two heads or...
at least 2 tails Answer : We know that, Probability of occurrence of an eventLet T be tails and H be heads Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH Desired outcomes are at...
Answer : We know that, Probability of occurrence of an event Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHHLet T be tails and H be heads Desired outcomes are at most two tails. So,...
Answer : We know that, Probability of occurrence of an event Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH Desired outcomes are exactly one tail. So, desired outputs are THH, HTH,...
Answer : We know that, Probability of occurrence of an event Let T be tails and H be heads Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH Desired outcomes are exactl two tails. So,...
Answer : We know that, Probability of occurrence of an event Let B be Boy and G be Girl Total possible outcomes are BB, BG, GB, GG Our desired outcome is at least one boy. So, BB, BG, GB are desired...
Answer : We know that, Probability of occurrence of an event Total no.of outcomes = 10+25 = 35 Desired outcomes are prizes. Total no.of desired outcomes = 10 Therefore, the probability of getting a...
Answer : We know that, Probability of occurrence of an event By permutation and combination, total no.of ways to pick r objects from given n objects is nCr Now, total no.of ways to pick a ball from...
Answer : We know that, Probability of occurrence of an event By permutation and combination, total no.of ways to pick r objects from given n objects is nCr Now, total no.of ways to pick a ball from...
Answer : We know that, Probability of occurrence of an event By permutation and combination, total no.of ways to pick r objects from given n objects is nCr Now, total no.of ways to pick a ball from...
Answer : We know that, Probability of occurrence of an event By permutation and combination, total no.of ways to pick r objects from given n objects is nCr Now, total no.of ways to pick a ball from...
Answer : We know that Probability of occurrence of an event By permutation and combination, total no.of ways to pick r objects from given n objects is nCr Now, total no.of ways to pick a ball from...
Answer : We know that, Probability of occurrence of an event By permutation and combination, total no.of ways to pick r objects from given n objects is nCr Now, total no.of ways to pick a ball from...
Answer : We know that, Probability of occurrence of an event (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3),...
Answer : We know that, Probability of occurrence of an event Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3,...
Answer : We know that, Probability of occurrence of an event Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3,...
Answer : We know that, Probability of occurrence of an event (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3),...
Answer : We know that, Probability of occurrence of an event (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3),...
Answer : We know that, Probability of occurrence of an event (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),Total outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3),...
Answer : (i) We know that, Probability of occurrence of an event (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),Outcomes are (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3),...
Answer : We know that, Probability of occurrence of an event As 4, 5 are two numbers between 3 and, so the desired outcomes are 3, 6, and total outcomes are 1, 2, 3, 4, 5, 6 3/6 Therefore, total...
Answer : We know that, Probability of occurrence of an event 2/6As 3, 6 are multiples up to 6, so the desired outcomes are 3, 6, and total outcomes are 1, 2, 3, 4, 5, 6 Therefore, total no.of...
Answer : We know that, Probability of occurrence of an event outcomes are 1, 2, 3, 4, 5, 6As 2, 3, 5 are prime numbers up to 6, so the desired outcomes are 2, 3, 5, and total 1/2 Conclusion:...
Answer : We know that, Probability of occurrence of an event outcomes are 1, 2, 3, 4, 5, 6As 1, 3, 5 are odd numbers up to 6, so the desired outcomes are 1, 3, 5, and total 2/3 Therefore, total...
Answer : We know that, Probability of occurrence of an event 2/3Total outcomes are 1, 2, 3, 4, 5, 6, and the desired outcomes are 2, 3 Therefore, total no.of outcomes are 6, and total no.of desired...
Answer : We know that, Probability of occurrence of an event Therefore, total no.of outcomes are 6, and total no.of desired outcomes are 1Total outcomes are 1, 2, 3, 4, 5, 6, and the desired outcome...
Answer : We know that Probability of occurrence of an event Hence the total no.of outcomes are 2 (i.e. heads and tails)Total outcomes of the coin are tails and heads And the desired output is tail....