Answer:
We can write the following set of equations:
θ1 = θ0 sin (wt + δ1) ………………………….(1)
θ2 = θ0 sin (wt + δ2) ……………………………..(2)
for first equation we have , θ = 2o
Upon putting this values, the equation (1) reduces to –
wt + δ1 = 90o
and for the second equation, we have θ = -1o
Similarly from (2), => wt + δ2 = – 30o
Therefore, upon equating te results we gte
δ1 – δ2 = 120o