Consider interference between two sources of intensities I and 4I. What will be the intensity at points where phase differences are:
Consider interference between two sources of intensities I and 4I. What will be the intensity at points where phase differences are:

Ans: We know that, I=a^{2}+b^{2}+2 a b \cos \phi
Where, a and b are amplitudes of two coherent waves that are having phase difference of \phi.
Here a^{2}=I, b^{2}=41

    \[\begin{array}{l} \Rightarrow|=|+4 \mid+2 \sqrt{\mid} \sqrt{4 \mid} \cos \phi \\ \Rightarrow|=5|+4 \mid \cos \phi \end{array}\]

When, \phi=\frac{\pi}{2}

    \[\begin{array}{l} \Rightarrow|=5|+4 \mid \cos \frac{\pi}{2} \\ \therefore|=5| \end{array}\]

Therefore, the intensity will be five times more.