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Home » Electronic configurations of four elements A, B, C and D are given below :                 Which of the following is the correct order of increasing tendency to gain electron :(i) A < C < B < D(ii) A < B < C < D(iii) D < B < C < A(iv) D < A < B < C
Electronic configurations of four elements A, B, C and D are given below :

    \[\left( \mathbf{A} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{6}}}~\]


    \[\left( \mathbf{B} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{4}}}\]


    \[\left( \mathbf{C} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{6}}}~\mathbf{3}{{\mathbf{s}}^{\mathbf{1}}}~\]


    \[\left( \mathbf{D} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{5}}}\]


Which of the following is the correct order of increasing tendency to gain electron :
(i) A < C < B < D
(ii) A < B < C < D
(iii) D < B < C < A
(iv) D < A < B < C
CBSE | Chemistry | Class 11 | Classification of Elements and Periodicity in Properties | NCERT Exemplar
Electronic configurations of four elements A, B, C and D are given below :

    \[\left( \mathbf{A} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{6}}}~\]


    \[\left( \mathbf{B} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{4}}}\]


    \[\left( \mathbf{C} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{6}}}~\mathbf{3}{{\mathbf{s}}^{\mathbf{1}}}~\]


    \[\left( \mathbf{D} \right)\text{ }\mathbf{1}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{s}}^{\mathbf{2}}}~\mathbf{2}{{\mathbf{p}}^{\mathbf{5}}}\]


Which of the following is the correct order of increasing tendency to gain electron :
(i) A < C < B < D
(ii) A < B < C < D
(iii) D < B < C < A
(iv) D < A < B < C

Option (i) is the answer.

(a) A – Is2 2s2 2p6 – Noble gas configuration

B -1s2 2s2 2p4 – 2 electrons short of stable configuration

C – 1s2 2s2 2p6 3.?1 – Requires one electron to complete 5-orbital

D -1s2 2s2 2p5 – Requires one electron to attain noble gas configuration

Because all of their orbitals are totally occupied, noble gases have no inclination to gain electrons. As a result, element A has the lowest enthalpy of electron gain.

Element D has the largest electron gain enthalpy, followed by element B, because element D has one electron less and element B has two electrons less than the comparable noble gas configuration.

Because element C only has one electron in its fifth orbital and thus requires another electron to complete it, its electron gain enthalpy is lower than that of element B. When all of the foregoing information is combined, the electron gain enthalpies of the four elements increase in the following order: A, C, B, and D.

 

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