Explain the structures of diborane and boric acid.
Explain the structures of diborane and boric acid.

Solution:

(a) Diborane
\mathrm{B}_{2} \mathrm{H}_{6} is a compound that does not have an electron. \mathrm{B}_{2} \mathrm{H}_{6} just has 12 electrons -6 \mathrm{e}^{-}of 6 \mathrm{H} molecules and 3 \mathrm{e}^{-}of 2 \mathrm{~B} iotas each. So none of the boron molecules has any electrons left subsequent to being blended in with 3 \mathrm{H} particles. \mathrm{X}-beam diffraction studies showed the diborane structure as:
Two boron and four-terminal molecules of hydrogen \left(\mathrm{H}_{\mathrm{t}}\right) lie one way, while the other two connecting particles of hydrogen \left(\mathrm{H}_{\mathrm{b}}\right) are in the surface opposite to the plane of boron iotas. Once, of the two molecules of hydrogen spanning, one particle of \mathrm{H} lies over the plane, and the other beneath the plane. The terminal bonds are standard twocentre two-electron \left(2 c-2 e^{-}\right)bonds, while the two bridgings (B-H-B) bonds are three-focus two-electron (3c \left.- 2 \mathrm{e}^{-}\right)bonds.
(b) Boric corrosive
Boric corrosive is organized in a layered structure. Each planar unit \mathrm{BO}_{3} is associated by molecules \mathrm{H} to one another. The \mathrm{H} molecules structure a covalent bond with a \mathrm{BO}_{3} unit while another \mathrm{BO}_{3} unit frames a hydrogen bond. The dabbed lines, in the given figure, address hydrogen bonds.