Answer:
iii) 2cos7xcos3x = cos (7x+3x) + cos (7x – 3x)
=cos10x + cos 4x
Using,
2cosAcosB = cos (A+ B) + cos (A – B)
iv)2sin8xsin2x = cos (8x – 2x) – cos (8x + 2x)
= cos6x – cos10x
Using,
2sinAsinB = cos (A – B) – cos (A+ B)
Answer:
iii) 2cos7xcos3x = cos (7x+3x) + cos (7x – 3x)
=cos10x + cos 4x
Using,
2cosAcosB = cos (A+ B) + cos (A – B)
iv)2sin8xsin2x = cos (8x – 2x) – cos (8x + 2x)
= cos6x – cos10x
Using,
2sinAsinB = cos (A – B) – cos (A+ B)