Figure shows the position-time graph of a particle of mass 4 kg. What is the (a) force on the particle for t 4 s, 0 < t < 4 s? (b) impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only).
Figure shows the position-time graph of a particle of mass 4 kg. What is the (a) force on the particle for t 4 s, 0 < t < 4 s? (b) impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only).

When t<0, the particle’s distance travelled is zero. As a result, the particle’s force is zero.

When 0< t< 4s occurs, the particle is travelling at a constant speed. As a result, there will be no force.

The particle remains at a fixed distance for t>4s. As a result, the particle’s force will be zero.

At t = 0, the impulse is zero.

u = 0 in this case.

0.75 m/s = v = 34

4 kg = M

mv – mu = m (v – u)

= 4 (0 – 0.75) = -3 kg m/s

Impulse at t= 4s

u = 0.75 m/s, v = 0

Impulse = m (v – u) = 4 (0 – 0.75) = -3 kg m/s