To Find: 23rd term of the AP
Given: The series is 7, 5, 3, 1, –1, –3, …
a1= 7, a2= 5 and d= 3–5= –2
(Where a=a1 is first term, a2 is second term, an is nth term and d is common difference
of given AP)
Formula Used: an = a + (n – 1)d
So put n =23 in above formula, we have
a23= a1 + (23 – 1)(–2) = 7– 44 = –37
So 23rd term of AP is equal to –37.
Find the 23rd term of the AP 7, 3, 1, –1, –3, …
Find the 23rd term of the AP 7, 3, 1, –1, –3, …