Answer:

The equation of a circle passing through the coordinates of the end points of diameters is (x – x₁) (x – x₂) + (y – y₁)(y – y₂) = 0

Substituting the values:(x₁, y₁) = (p, q) & (x₂, y₂) = (r, s)

(x – p)(x – r) + (y – q)(y – s) = 0

x² – rx – px + pr + y² – sy – qy + qs = 0

x² + y² – (r + p)x – (s + q)y + (pr + qs) = 0