Find the equation of the circle which touches the both axes in first quadrant and whose radius is a.
Find the equation of the circle which touches the both axes in first quadrant and whose radius is a.

The circle touches both the x and y axes in the first quadrant and the radius is a.

NCERT Exemplar Solutions for Class 11 Maths Chapter 11 - Image 1

For a circle of radius a, the centre is (a, a).

The equation of a circle having centre (h, k), having radius as r units, is

    \[{{\left( x\text{ }-\text{ }h \right)}^{2}}~+\text{ }{{\left( y\text{ }-\text{ }k \right)}^{2}}~=\text{ }{{r}^{2}}\]

Hence, the equation of the circle is

    \[\begin{array}{*{35}{l}} {{\left( x\text{ }-\text{ }a \right)}^{2}}~+\text{ }{{\left( y\text{ }-\text{ }a \right)}^{2}}~=\text{ }{{a}^{2}}  \\ {{x}^{2}}~\text{ }-2ax\text{ }+\text{ }{{a}^{2}}~+\text{ }{{y}^{2}}~\text{ }-2ay\text{ }+\text{ }{{a}^{2}}~-\text{ }{{a}^{2}}~=\text{ }0  \\ {{x}^{2}}~\text{ }-2ax\text{ }+\text{ }{{y}^{2}}~\text{ }-2ay\text{ }+\text{ }{{a}^{2}}~=\text{ }0  \\ \end{array}\]