Find the equation of the ellipse whose foci are (4, 0) and (- 4, 0), eccentricity = 1/3.
Find the equation of the ellipse whose foci are (4, 0) and (- 4, 0), eccentricity = 1/3.

Given:

Foci are

    \[\left( 4,\text{ }0 \right)\text{ }\left( -\text{ }4,\text{ }0 \right)\]

Eccentricity

    \[=\text{ }1/3\]

Now let us find the equation to the ellipse.

We know that the equation of the ellipse whose axes are x and y – axis is given as
RD Sharma Solutions for Class 11 Maths Chapter 26 – Ellipse - image 66

By using the formula,

Eccentricity:

RD Sharma Solutions for Class 11 Maths Chapter 26 – Ellipse - image 67

RD Sharma Solutions for Class 11 Maths Chapter 26 – Ellipse - image 68

It is given that foci

    \[=\text{ }\left( 4,\text{ }0 \right)\text{ }\left( -\text{ }4,\text{ }0 \right)\text{ }=>\text{ }foci\text{ }=\text{ }\left( \pm ae,0 \right)\]

Where,

    \[ae\text{ }=\text{ }4\]

    \[a\left( 1/3 \right)\text{ }=\text{ }4\]

Or,

    \[a\text{ }=\text{ }12\]

    \[{{a}^{2}}~=\text{ }144\]

By substituting the value of

    \[{{a}^{2}}\]

we get

    \[{{b}^{2}}~=\text{ }8{{a}^{2}}/9\]

    \[{{b}^{2}}~=\text{ }8\left( 144 \right)/9\]

So,

    \[=\text{ }128\]

So the equation of the ellipse can be given as

RD Sharma Solutions for Class 11 Maths Chapter 26 – Ellipse - image 69