Let the equation of line AB be 4x – 3y + 5 = 0 and point C be (0, 0)
CD is perpendicular to the line AB, and we need to find:
- Equation of Perpendicular drawn from point C
- Coordinates of D
Let the coordinates of point D be (a, b)
Also, point D(a, b) lies on the line AB, i.e. point (a, b) satisfy the equation of line AB Putting x = a and y = b, in equation, we get
4a – 3b + 5 = 0 …(i)
Also, the CD is perpendicular to the line AB
and we know that, if two lines are perpendicular then the product of their slope is equal to -1
∴ Slope of AB × Slope of CD = -1