Solution:
It is known to us that the eq. of a plane passing through is given by
Where, A, B, C are the direction ratios of normal to the plane.
It is given that the plane passes through
Therefore, eq. of plane is given by
As this plane is perpendicular to the given two planes. Therefore, their normal to the plane would be perpendicular to normal of both planes.
It is known to us that
is perpendicular to both and
Therefore, required normal is cross product of normal of planes
and
Therefore, the direction ratios are
Substituting the obtained values in eq.(1), we obtain
As a result, the eq. of the required plane is .