Find the equation of the plane through the line of intersection of the planes x – 3y + z + 6 = 0 and x + 2y + 3z + 5 = 0, and passing through the origin.
Find the equation of the plane through the line of intersection of the planes x – 3y + z + 6 = 0 and x + 2y + 3z + 5 = 0, and passing through the origin.

Answer:

Cartesian form of equation of plane through the line of intersection of planes:

– x – 27y – 13z = 0

Multiplying by negative sign,

x + 27y + 13z = 0

The equation of the plane is x + 27y + 13z = 0.