Putting the value of y1 = 4 – x1 in equation 3, we get
Putting the value of x1 in equation 4, we get
Hence, the required points on the given line are (3, 1) and (-7, 11)
Putting the value of y1 = 4 – x1 in equation 3, we get
Putting the value of x1 in equation 4, we get
Hence, the required points on the given line are (3, 1) and (-7, 11)