Given: The sum of first n terms.
To Find: The rth term.
Let the first term be a and common difference be d
Put n = 1 to get the first term
a = S1 = 3 + 2 = 5
Put n = 2 to get a + (a + d)2a + d = 12 + 4 = 1610 + d = 16d = 6tr = a + (r – 1)d
t �r = 5 + (r – 1)6 = 5 + 6r – 6 = 6r – 1
The rth term is given by 6r – 1.