The integers between 100 and 600 divisible by 5 and leaves remainder 2 are
102, 107, 112, 117,…, 597.
To Find: Sum of the above AP
Here a = 102, d = 5, l = 597
a + (n – 1)d = 597
⇒102 + 5(n – 1) = 597
⇒ (n – 1) = 99
⇒ n = 100

Now,

⇒ S = 50[204 + 495] = 50 × 699 = 34950
The sum of all such integers is 34950.