To Find: The sum of the given series.
The nth term of an AP series is given by
tn = a + (n – 1)d
⇒191 = 2 + (n – 1)3
⇒3(n – 1) = 189
⇒ n – 1 = 63
⇒ n = 64
Therefore,
The sum of the series is 6176.
To Find: The sum of the given series.
The nth term of an AP series is given by
tn = a + (n – 1)d
⇒191 = 2 + (n – 1)3
⇒3(n – 1) = 189
⇒ n – 1 = 63
⇒ n = 64
Therefore,
The sum of the series is 6176.