Solution:-

To find the value of sin 35^o 22’,

We read the table of natural sines in the horizontal line which begins with 35^o

In the vertical column headed by 22’ i.e. 22’ – 18’ = 4’ in the difference column, the value of 4’ in mean difference column is 10.

Then, value that we find in vertical column is 0.5779

Now adding the value of 18’ and 4’ = 0.5779 + 10

= 0.5789

Therefore, the value of sin 35^o 22’ is obtained as under,

sin 35^o 22’ = 0.5779 … [from table]

Mean difference for 4’ = 10 … [to be added]

Then, sin 35^o 22’ = 0.5789