Find the vector and Cartesian equations of the line passing through the points A(2, -3, 0) and B(-2, 4, 3).
Find the vector and Cartesian equations of the line passing through the points A(2, -3, 0) and B(-2, 4, 3).

Find the vector and Cartesian equations of the line passing through the points A(2,-3,0) and B(-2,4,, 3).
Answer
Given: line passes through the points (2,-3,0) and (-2,4,3)
To find: equation of line in vector and Cartesian forms
Formula Used: Equation of a line is
Vector form: \overrightarrow{\overrightarrow{1}}=\vec{a}+\overrightarrow{\mathrm{b}}
Cartesian form: \frac{\mathrm{x}-\mathrm{x}_{1}}{\mathrm{~b}_{n}}=\frac{\mathrm{y}-\mathrm{y}_{1}}{\mathrm{~b}_{z}}=\frac{\mathrm{z}-\mathrm{z}_{1}}{\mathrm{~h}_{\mathrm{j}}}=\lambda
where \vec{a}=\mathrm{x}_{1} \hat{i}+\mathrm{y}_{1} \hat{l}+\mathrm{z}_{1} \hat{k} is a point on the line and \overrightarrow{\mathrm{b}}=\mathrm{b}_{1} \hat{1}+\mathrm{h}_{2} \hat{\jmath}+\mathrm{b}_{3} \hat{k} with \mathrm{b}_{1}: \mathrm{b}_{2}: \mathrm{b}_{3} being the direction ratios of the line.
Explanation:
Here, \overrightarrow{\vec{\lambda}}=2 \hat{i}-3 \hat{i}
The direction ratios of the line are (2+2):(-3-4):(0-3)

4:7:3
\Rightarrow 4:-7:-3
4:7:3 So, b=4i^+7^+3k^
\begin{array}{l}
\Rightarrow-4: 7: 3 \\
\text { So, } \overrightarrow{\mathrm{b}}=-4 \hat{i}+7 \hat{\mid}+\overrightarrow{3} \hat{k}
\end{array}

Therefore,
Vector form:

r=2ı^3ȷ^+λ(4ı^+7ȷ^+3k^)
\overrightarrow{\mathrm{r}}=2 \hat{\imath}-3 \hat{\jmath}+\lambda(-4 \hat{\imath}+7 \hat{\jmath}+3 \hat{k})

Cartesian form:

x2x=y+37=z3
\frac{x-2}{-x}=\frac{y+3}{7}=\frac{z}{3}