Find what the given equation becomes when the origin is shifted to the point (1, 1)
Find what the given equation becomes when the origin is shifted to the point (1, 1)

x2 – y2 – 2x + 2y = 0

Answer : Let the new origin be (h, k) = (1, 1) Then, the transformation formula become:

x = X + 1 and y = Y + 1

Substituting the value of x and y in the given equation, we get x2 – y2 – 2x + 2y = 0

Thus,

(X + 1)2 – (Y + 1)2 – 2(X + 1) + 2(Y + 1) = 0

⇒ (X2 + 1 + 2X) – (Y2 + 1 + 2Y) – 2X – 2 + 2Y + 2 = 0

⇒ X2 + 1 + 2X – Y2 – 1 – 2Y – 2X + 2Y = 0

⇒ X2 – Y2 = 0

Hence, the transformed equation is X2 – Y2 = 0