Fluorine reacts with ice and results in the change: \mathrm{H}_{2} \mathrm{O}_{(s)}+F_{2}(g) \rightarrow H F_{(g)}+\mathrm{HOF}_{(g)} Justify that this reaction is a redox reaction
Fluorine reacts with ice and results in the change: \mathrm{H}_{2} \mathrm{O}_{(s)}+F_{2}(g) \rightarrow H F_{(g)}+\mathrm{HOF}_{(g)} Justify that this reaction is a redox reaction

Solution:

H_{2} O_{(s)}+F_{2}(g) \rightarrow H F_{(g)}+H O F_{(g)}

In the above response,

Oxidation no. of \mathrm{H} and \mathrm{O} in \mathrm{H}_{2} \mathrm{O} is +1 and -2 individually.

Oxidation no. of F_{2} is 0 .

Oxidation no. of \mathrm{H} and \mathrm{F} in HF is +1 and -1 individually.

Oxidation no. of \mathrm{H}, 0 and F in HOF is +1,- 2 and +1 individually.

The oxidation no. of F expanded from 0 in F_{2} to +1 in HOF.

The oxidation no. of F diminished from 0 in O_{2} to -1 in HF.

Accordingly, F is both diminished just as oxidized. In this way, it is redox response