5000 Ao = 5000 × 10-10 m
1/d = 2 sin β/1.22λ
dmin = 1.22 λ/ 2 sin β
λd = 1.22/10 × 10-10 m
When the 100V light is used, d’min = 1.22 λd/ 2 sin β
d’min = 1.22 × 1.22 × 10-10/2 sin β
The required ratio = dmin/d’min = 1.22/5000 = 0.244 × 10-3
For the same objective, find the ratio of the least separation between two points to be distinguished by a microscope for light of 5000 Ao and electrons accelerated through 100V used as the illuminating substance.
For the same objective, find the ratio of the least separation between two points to be distinguished by a microscope for light of 5000 Ao and electrons accelerated through 100V used as the illuminating substance.