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Home » How many tertiary carbon atoms and primary carbon atoms respectively are present in 2-iodo-3, 3-dimethyl pentane?
How many tertiary carbon atoms and primary carbon atoms respectively are present in 2-iodo-3, 3-dimethyl pentane?
Chemistry | Chemistry | MHTCET
How many tertiary carbon atoms and primary carbon atoms respectively are present in 2-iodo-3, 3-dimethyl pentane?
  1. 2,4
  2. 0,4
  3. 2,3
  4. 1,3

Solution: 0,4

We can represent 2-iodo-3, 3-dimethyl pentane as follows:

{{H}_{3}}C-CH(I)-C{{(C{{H}_{3}})}_{2}}-C{{H}_{2}}-C{{H}_{3}}

As we can see that there are zero carbon atoms bound to three other carbon atoms, so there are zero tertiary carbon atoms. A primary carbon is a carbon atom that is bound to only one other carbon atom and as we can see there are four primary carbon atoms.

i

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