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Home » If dimensions of critical velocity of a liquid flowing through a tube are expressed as , where and are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of and are given by: (1) (2) (3) (4)
If dimensions of critical velocity v_{c} of a liquid flowing through a tube are expressed as \left[\eta^{x} \rho^{y} r^{2}\right], where \eta, \rho and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by: (1) \quad 1,1,1 (2) 1,-1,-1 (3) -1,-1,1 (4) \quad-1,-1,-1
Physics | Physics
If dimensions of critical velocity v_{c} of a liquid flowing through a tube are expressed as \left[\eta^{x} \rho^{y} r^{2}\right], where \eta, \rho and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by: (1) \quad 1,1,1 (2) 1,-1,-1 (3) -1,-1,1 (4) \quad-1,-1,-1

Solution: (2)
\mathrm{V}_{\mathrm{c}}=\eta^{\mathrm{x}} \rho^{\mathrm{y}} \mathrm{r}^{\mathrm{z}}
Critical velocity is given by V_{c}=\frac{R \eta}{2 \rho r}
So, x=1
\begin{aligned} y=-1 \\ z=-1 \end{aligned}

i

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