(1) [F][A][T] (2) [F][A][T2]
(3) [F][A][T–1] (4) [F][A–1][T]
Solution: Answer (2)
We know that,
[E] = [Fa][Ab][Tc]
=> [ML2T–2] = [MLT–2]a [LT–2]b [T]c
[ML2T–2] = [MaL a + b T–2a – 2b + c]
Comparing dimensions on both sides, we get:
a = 1; a + b = 2 and –2 = – 2a – 2b + c
b = 1 and c = 2
[E] = [FAT2]