Solution:

We know that,

P(E)+P(not E) = 1

A/Q

It is given that, P(E) = 0.05

So, P(not E) = 1-P(E)

Or, P(not E) = 1-0.05

∴ P(not E) = 0.95

If P(E) = 0.05, what is the probability of P(not E)?

If P(E) = 0.05, what is the probability of P(not E)?

Solution:

We know that,

P(E)+P(not E) = 1

A/Q

It is given that, P(E) = 0.05

So, P(not E) = 1-P(E)

Or, P(not E) = 1-0.05

∴ P(not E) = 0.95