Solution:
We know that,
P(E)+P(not E) = 1
A/Q
It is given that, P(E) = 0.05
So, P(not E) = 1-P(E)
Or, P(not E) = 1-0.05
∴ P(not E) = 0.95
If P(E) = 0.05, what is the probability of P(not E)?
If P(E) = 0.05, what is the probability of P(not E)?
Solution:
We know that,
P(E)+P(not E) = 1
A/Q
It is given that, P(E) = 0.05
So, P(not E) = 1-P(E)
Or, P(not E) = 1-0.05
∴ P(not E) = 0.95