Given: tan θ+ sec θ = l … eq. 1
Duplicating and isolating by (sec θ – tan θ) on numerator and denominator of L.H.S,
Along these lines, sec θ – tan θ = 1 … eq.2
Adding eq. 1and eq. 2, we get
Henceforth, demonstrated.
Given: tan θ+ sec θ = l … eq. 1
Duplicating and isolating by (sec θ – tan θ) on numerator and denominator of L.H.S,
Along these lines, sec θ – tan θ = 1 … eq.2
Adding eq. 1and eq. 2, we get
Henceforth, demonstrated.