If two coins are tossed once, what is the probability of getting: \[\left( \mathbf{iii} \right)~\]both heads or both tails

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If two coins are tossed once, what is the probability of getting:

$\left( \mathbf{iii} \right)~$

both heads or both tails

If two coins are tossed once, what is the probability of getting:

$\left( \mathbf{iii} \right)~$

both heads or both tails

Solution:

$\left( iii \right)$

E = event of getting both heads or both tails

$=\text{ }\left\{ HH,\text{ }TT \right\}$

$n\left( E \right)\text{ }=\text{ }2$

Hence, probability of getting both heads or both tails

$=~n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }2/4\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}$

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