If two coins are tossed once, what is the probability of getting: (i) both heads. (ii) at least one head.
If two coins are tossed once, what is the probability of getting: (i) both heads. (ii) at least one head.

Solution:

We know that, when two coins are tossed together possible number of outcomes = {HH, TH, HT, TT}

So, n(S) = 4

(i) E = event of getting both heads = {HH}

n(E) = 1

Hence, probability of getting both heads = n(E)/ n(S) = ¼

(ii) E = event of getting at least one head = {HH, TH, HT}

n(E) = 3

Hence, probability of getting at least one head = n(E)/ n(S) = ¾