If two coins are tossed once, what is the probability of getting: (i) both heads. (ii) at least one head.
If two coins are tossed once, what is the probability of getting: (i) both heads. (ii) at least one head.

Solution:

We know that, when two coins are tossed together possible number of outcomes = {HH, TH, HT, TT}

So,

    \[n\left( S \right)\text{ }=\text{ }4\]

    \[\left( i \right)\]

E = event of getting both heads = {HH}

    \[n\left( E \right)\text{ }=\text{ }1\]

Hence, probability of getting both heads

    \[=~n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_4}\]

    \[\left( ii \right)\]

E = event of getting at least one head = {HH, TH, HT}

    \[n\left( E \right)\text{ }=\text{ }3\]

Hence, probability of getting at least one head

    \[=~n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }{\scriptscriptstyle 3\!/\!{ }_4}\]