If y=\sin (\log x), then \frac{d y}{d x}= (a) \frac{1}{x} \cos (\log x) (b) \frac{1}{x} \sin (\log x) (c) 0 (d) 1
If y=\sin (\log x), then \frac{d y}{d x}= (a) \frac{1}{x} \cos (\log x) (b) \frac{1}{x} \sin (\log x) (c) 0 (d) 1

Sol:
Correct option is (A)\frac{1}{x} \cos (\log x)