For the situation given in the equation, we have

Probability of getting a six in a throw of a die

Also, probability of not getting a

Following that, there are three scenarios from which it is possible to compute the expected value of the amount that he wins:

As an example, consider the following scenario: He receives a six on his first try, and so meets the required probability be

Amount received by him = Rs. 1

(ii) Secondly, if he gets six on his second throw then the probability

Amount received by him = – Rs. 1 + Rs. 1

(iii) Finally, if he does not get a six in his first two throws but does get a six in his third throw, the probability of getting a six is increased.

Amount received by him = – Rs. 1 – Rs. 1 + Rs. 1

Hence, expected value that he can