In a single throw of a die, find the probability that the number: \[\left( \mathbf{iii} \right)\]will be an odd number

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In a single throw of a die, find the probability that the number:

$\left( \mathbf{iii} \right)$

will be an odd number

In a single throw of a die, find the probability that the number:

$\left( \mathbf{iii} \right)$

will be an odd number

Solution:

$\left( iii \right)$

If

$E\text{ }=$

event of getting an odd number

$=\text{ }\left\{ 1,\text{ }3,\text{ }5 \right\}$

So

$,\text{ }n\left( E \right)\text{ }=\text{ }3$

Then, probability of a getting an odd number

$=\text{ }n\left( E \right)/\text{ }n\left( s \right)\text{ }=\text{ }3/6\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}$

i

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