In a single throw of a die, find the probability that the number: (i) will be an even number. (ii) will not be an even number.
In a single throw of a die, find the probability that the number: (i) will be an even number. (ii) will not be an even number.

Solution:

Here, the sample space = {1, 2, 3, 4, 5, 6}

n(s) = 6

(i) If E = event of getting an even number = {2, 4, 6}

n(E) = 3

Then, probability of a getting an even number = n(E)/ n(s) = 3/6 = ½

(ii) If E = event of not getting an even number = {1, 3, 5}

n(E) = 3

Then, probability of a not getting an even number = n(E)/ n(s) = 3/6 = ½