In a single throw of a die, find the probability of getting a number: (i) greater than 4. (ii) less than or equal to 4.
In a single throw of a die, find the probability of getting a number: (i) greater than 4. (ii) less than or equal to 4.

Solution:

Here, the sample space = {1, 2, 3, 4, 5, 6}

So, n (s) = 6

(i) If E = event of getting a number greater than 4 = {5, 6}

So, n (E) = 2

Then, probability of getting a number greater than 4 = n(E)/ n(s) = 2/6 = 1/3

(ii) If E = event of getting a number less than or equal to 4 = {1, 2, 3, 4}

So, n (E) = 4

Then, probability of getting a number less than or equal to 4 = n(E)/ n(s) = 4/6 = 2/3