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Home » In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference (1) (2) (3) (4)
In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference (1) 11 \frac{\lambda}{2} (2) 5 \frac{\lambda}{2} (3) 10 \frac{\lambda}{2} (4) 9 \frac{\lambda}{2}
Physics | Physics
In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference (1) 11 \frac{\lambda}{2} (2) 5 \frac{\lambda}{2} (3) 10 \frac{\lambda}{2} (4) 9 \frac{\lambda}{2}

Answer (4)
Sol. Path difference for destructive interference in YDSE
\begin{array}{c} \Rightarrow \Delta X_{n}=\frac{(2 n-1)}{2} \lambda \quad n=1,2,3 \ldots . \\ \Delta X_{5^{k+}}=\left(\frac{2 \times 5-1}{2}\right) \lambda=\frac{9 \lambda}{2} \end{array}

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