(A) 60°

(B) 70°

(C) 80°

(D) 90°

Answer:

The radius of the circle to the tangent PT is OP, and the radius to the tangents TQ is OQ, as stated in the question.

As a result, OP ⊥ PT and TQ ⊥ OQ

Therefore, ∠OQT = ∠OPT = 90°

Now, we know that the sum of the interior angles in the quadrilateral POQT is 360°.

As a result, ∠PTQ+∠POQ+∠OPT+∠OQT = 360°

Now, put the respective values in the above equation we get,

∠PTQ +90°+110°+90° = 360°

∠PTQ = 70°

As a result, option B is correct i.e. ∠PTQ is 70°.