Answer : By using the formula (n-1)! (Mention in Solution-1) So 8 persons can be arranged by 7!
Now each person have the same neighbour in the clockwise and anticlockwise arrangement
Total number of arrangement are (7!)/2 = 2520
In how many ways can 8 persons be seated at a round table so that all shall not have the same neighbour in any two arrangement?
In how many ways can 8 persons be seated at a round table so that all shall not have the same neighbour in any two arrangement?