A potential difference of 4V is applied in series to two resistors of 6 and 2. Calculate: the difference in voltage across the six resistors

Answer:

 

Given,

 

V = 4V

 

R1 = 6 Ω

 

R2 = 2 Ω

 

Combined resistance, R = R1 + R2 = 8 ohm

 

Current flowing, I = V/R = 4/8 = 0.5 amp

 

Difference in potential across a 6 ohm resistor = IR1 = 3V