Answers:
(i)
Consider,
a, b ∈ Q – {-1}
a * b = a + b + ab
= b + a + ba
= b * a
a * b = b * a, ∀ a, b ∈ Q – {-1}
a * (b * c) = a * (b + c + b c)
= a + (b + c + b c) + a (b + c + b c)
= a + b + c + b c + a b + a c + a b c
(a * b) * c = (a + b + a b) * c
= a + b + a b + c + (a + b + a b) c
= a + b + a b + c + a c + b c + a b c
a * (b * c) = (a * b) * c, ∀ a, b, c ∈ Q – {-1}
Hence, * is associative on Q – {-1}.
(ii)
Consider,
e be the identity element in I+ with respect to *
a * e = a = e * a, ∀ a ∈ Q – {-1}
a * e = a and e * a = a, ∀ a ∈ Q – {-1}
a + e + ae = a and e + a + ea = a, ∀ a ∈ Q – {-1}
e + ae = 0 and e + ea = 0, ∀ a ∈ Q – {-1}
e (1 + a) = 0 and e (1 + a) = 0, ∀ a ∈ Q – {-1}
e = 0, ∀ a ∈ Q – {-1} [because a not equal to -1]
Hence, 0 is the identity element in Q – {-1} with respect to *.