Mark (√) against the correct answer in the following: The general solution of the $D E \frac{d y}{d x}+y \tan x=\sec x^{\text {is }}$ A. $y=\sin x-\mathrm{C} \cos x$ B. $y=\sin x+\mathrm{C} \cos x$ C. $y=\cos x-\mathrm{C} \sin x$ D. None of these

Home » Mark (√) against the correct answer in the following: The general solution of the A. B. C. D. None of these

Mark (√) against the correct answer in the following: The general solution of the $D E \frac{d y}{d x}+y \tan x=\sec x^{\text {is }}$
A. $y=\sin x-\mathrm{C} \cos x$
B. $y=\sin x+\mathrm{C} \cos x$
C. $y=\cos x-\mathrm{C} \sin x$
D. None of these

CBSE | Class 12 | Linear Differential Equations | Maths | RS Aggarwal

Mark (√) against the correct answer in the following: The general solution of the $D E \frac{d y}{d x}+y \tan x=\sec x^{\text {is }}$
A. $y=\sin x-\mathrm{C} \cos x$
B. $y=\sin x+\mathrm{C} \cos x$
C. $y=\cos x-\mathrm{C} \sin x$
D. None of these

Solution:

$\frac{\mathrm{dy}}{\mathrm{dx}}+\mathrm{y} \tan \mathrm{x}=\mathrm{Secx}$
Comparing with $\frac{d y}{d x}+P y=Q$
Integrating factor $e^{\int \tan x d x}=\operatorname{Sec} x$
General solution y $\operatorname{Sec} x=\int \operatorname{Sec} x . \operatorname{Sec} x d x+c$
$y \sec x=\tan x+C$ $y=\sin x+C \cos x$