Match the corresponding entries of column 1 with column 2. [Where \mathbf{m} is the magnification produced by the mirror]
A \mathrm{A} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{B} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{C} \rightarrow \mathrm{b} and \mathrm{d} ; \mathrm{D} \rightarrow \mathrm{a} and \mathrm{d}
B \mathrm{A} \rightarrow \mathrm{a} and \mathrm{c} ; \mathrm{B} \rightarrow \mathrm{a} and \mathrm{d} ; \mathrm{C} \rightarrow \mathrm{a} and b; \mathrm{D} \rightarrow \mathrm{c} and \mathrm{d}
C \mathrm{A} \rightarrow \mathrm{a} and \mathrm{d} ; \mathrm{B} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{C} \rightarrow \mathrm{b} and \mathrm{d} ; \mathrm{D} \rightarrow \mathrm{b} and \mathrm{c}
D \mathrm{A} \rightarrow \mathrm{c} and \mathrm{d} ; \mathrm{B} \rightarrow \mathrm{b} and \mathrm{d} ; \mathrm{C} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{D} \rightarrow \mathrm{a} and \mathrm{d}
Match the corresponding entries of column 1 with column 2. [Where \mathbf{m} is the magnification produced by the mirror]
A \mathrm{A} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{B} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{C} \rightarrow \mathrm{b} and \mathrm{d} ; \mathrm{D} \rightarrow \mathrm{a} and \mathrm{d}
B \mathrm{A} \rightarrow \mathrm{a} and \mathrm{c} ; \mathrm{B} \rightarrow \mathrm{a} and \mathrm{d} ; \mathrm{C} \rightarrow \mathrm{a} and b; \mathrm{D} \rightarrow \mathrm{c} and \mathrm{d}
C \mathrm{A} \rightarrow \mathrm{a} and \mathrm{d} ; \mathrm{B} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{C} \rightarrow \mathrm{b} and \mathrm{d} ; \mathrm{D} \rightarrow \mathrm{b} and \mathrm{c}
D \mathrm{A} \rightarrow \mathrm{c} and \mathrm{d} ; \mathrm{B} \rightarrow \mathrm{b} and \mathrm{d} ; \mathrm{C} \rightarrow \mathrm{b} and \mathrm{c} ; \mathrm{D} \rightarrow \mathrm{a} and \mathrm{d}

Correct Option A

Answer:

The term “positive magnification” refers to an image that is upright in relation to the object.
Negative magnification refers to an image that is inverted in relation to the object.
When the magnification is greater than one, the image size is larger than the object size, and when the magnification is less than one, the image size is smaller.

In the case of convex mirrors, the image is always smaller and more upright, so 0<m<1
In the case of a concave mirror image, m>1 and m<0 are inverted-small, inverted-large, and upright-large, respectively.
The only way to create a real image is to use a concave mirror, which can produce inverted-small or inverted-large images. As a result, m<0
Concave mirrors produce upright-large virtual images, whereas convex mirrors produce upright-small virtual images. As a result, m>0