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Home » An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
CBSE | Class 10 | Light Reflection and Refraction | NCERT Exemplar | Science
An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

Answer-

According to the question, height of the Object h0 is 5 cm

And the distance of the object from converging lens (u) is -25 cm

Also the Focal length of a converging lens is f = 10 cm

Making use of the lens formula,

1/v – 1/u = 1/f

1/v = 1/f + 1/u = 1/10 – 1/25 = 15/250

Therefore, v = 250/15

v = 16.66 cm

Also we know that for a converging lens magnification is given by –

m = hi/h0 and

m = – v/u

Therefore, we can write –

hi/h0 = – v/u

Therefore, the height of image is 3.3cm and it is inverted. As a result, the image is inverted and measured 3.3 cm at a distance of 16.7 cm behind the lens. The following is a ray diagram.

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