(iii) From numbers 2 to 10, there is one number which is an even number as well as multiple of 3 i.e. 6
So, favorable number of events = n(E) = 1
Hence, probability of selecting a card with a number which is an even number as well as multiple of 3
= n(E)/ n(S) = 1/9
(iv) From numbers 2 to 10, there are 7 numbers which are even numbers or a multiple of 3 i.e. 2, 3, 4, 6, 8, 9, 10
So, favorable number of events = n(E) = 7
Hence, probability of selecting a card with a number which is an even number or a multiple of 3
= n(E)/ n(S) = 7/9