(iii) From numbers 2 to 10, there is one number which is an even number as well as multiple of 3 i.e. 6

So, favorable number of events = n(E) = 1

Hence, probability of selecting a card with a number which is an even number as well as multiple of 3

= n(E)/ n(S) = 1/9

(iv) From numbers 2 to 10, there are 7 numbers which are even numbers or a multiple of 3 i.e. 2, 3, 4, 6, 8, 9, 10

So, favorable number of events = n(E) = 7

Hence, probability of selecting a card with a number which is an even number or a multiple of 3

= n(E)/ n(S) = 7/9